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- // The first argument is array of length <math>2^q</math> for some natural number $q$. If the numeration of elements of the array begins with zero, and the n3 KB (416 words) - 07:55, 10 September 2020
- Let ''k''<sub>1</sub>, ''k''<sub>2</sub>, ..., ''k''<sub>m</sub> be [[natural number]]s giving a [[Partition (mathematics)|partition]] of ''n'':2 KB (365 words) - 06:50, 22 January 2009
- ...r is conventionally denoted by ''Z'' and is by definition a non-negative [[natural number]]. For instance, the element [[carbon]] is characterized by ''Z'' = 6 and t7 KB (1,066 words) - 05:40, 6 March 2024
- ...<math>X^2=\left(0,0,1,0,0,\dots\right)</math>. More generally, for each [[natural number]] <math>n</math>, one can verify that the <math>n</math>-th power of <math>10 KB (1,741 words) - 10:04, 3 January 2009
- sometimes also called '''highest common factor''') of two or more [[natural number]]s5 KB (797 words) - 04:57, 21 April 2010
- ...the [[chemical element]]s can be characterized uniquely by non-negative [[natural number]]s, always denoted by ''Z''. For instance, the element [[carbon]] is charac4 KB (656 words) - 13:00, 7 July 2008
- ...how that the relation of divisibility is a [[partial order]] in the set of natural number <math>\mathbb{N},</math> and also in <math>\mathbb{Z}_+</math>35 KB (5,836 words) - 08:40, 15 March 2021
- For a given natural number <math>N</math> operator <math>\mathrm{DCTIII}_N</math> converts any array < For the simple and efficient implementation, <math>N=2^q</math> for some natural number <math>q</math>. Note that the size of the arrays is for unity smaller than8 KB (1,204 words) - 18:09, 8 September 2020
- For the discrete approximation of this operator, assume some large natural number <math>N</math>. Let <math>x_n=\sqrt{\pi/N}~ n</math>. Assume some large natural number <math>N</math>. Let <math>\displaystyle x_n=\frac{\pi}{N} n</math>. For app11 KB (1,680 words) - 18:00, 8 September 2020
- ...ation]] as follows: A number <math>\scriptstyle p \in \mathbb{N}</math> ([[natural number]]) is prime if for any <math>\scriptstyle a, b \in \mathbb{N}</math> such t14 KB (2,281 words) - 12:20, 13 September 2013
- ...ably many sets of the form treated in G ("7" being replaced with arbitrary natural number). Still a Borel set!2 KB (402 words) - 20:47, 30 June 2009
- ...scribed above as the set of ''R''-valued functions on the set '''N''' of [[natural number]]s (including zero) and defining the ''[[support (mathematics)|support]]''4 KB (604 words) - 23:54, 20 February 2010
- The grid points <math>x_j</math>, <math>j=0..N</math> are chosen for [[natural number]] <math>~j~</math>; <math>~0\!\le \! j \!<\! N</math> in the following way It is convenient to chose <math>N=2^m</math> for some natural number <math>m</math>; then the fast implementation of such a summation is especia11 KB (1,589 words) - 08:58, 9 September 2020
- Every natural number <math>\scriptstyle N > 1</math> can be written as a product of prime factor ...ation]] as follows: A number <math>\scriptstyle p \in \mathbb{N}</math> ([[natural number]]) is prime if for any <math>\scriptstyle a, b \in \mathbb{N}</math> such t18 KB (2,917 words) - 10:27, 30 August 2014
- [[Natural number]]3 KB (321 words) - 04:32, 22 November 2023
- * Let ''M'' be the [[natural number]]s (including zero) with addition as the operation. The corresponding conv2 KB (338 words) - 17:41, 23 December 2008
- ...;∧ ''n'' >2 ⇔ ''n'' = 3 when ''n'' is a [[natural number]]. ... ∨ ''n'' ≤ 2 ⇔ ''n'' ≠ 3 when ''n'' is a [[natural number]].9 KB (1,308 words) - 13:37, 16 July 2011
- ; If n is a natural number, we define the factorial of n as:9 KB (1,405 words) - 08:29, 2 March 2024
- :: This is true for links like [[Natural Number]], but not if you search for "Natural Number" in the search box at the top of the page. [[User:Peter Schmitt|Peter Schmi6 KB (959 words) - 03:47, 22 November 2023
- Let ''n'' be a natural number and denote by Small(''<u>n</u>'') a sentence whose intended meaning is ''"a On the other hand from these formulas given any natural number ''n'', by applying MP (Modus Ponens) rule several times we can prove that a10 KB (1,611 words) - 22:55, 20 February 2010