Talk:Sturm-Liouville theory: Difference between revisions
imported>David E. Volk (→Bessel equation in S-L form: Nevermind, I see it now) |
imported>Paul Wormer (→Error: new section) |
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Redacted comment. I see it now. | Redacted comment. I see it now. | ||
== Error == | |||
It seems to me that the article contains an error. Consider the equation: | |||
: <math>L u = {1 \over w(x)} \left(-{d\over dx}\left[p(x){du\over dx}\right]+q(x)u \right)</math> | |||
Contrary to what is implied in the article, the operator ''L'' is ''not'' self-adjoint, unless 1/''w''(''x'') commutes with the operator to its right. This in general not the case. The proper way to transform is | |||
:<math> | |||
L u = wu\; \Longrightarrow\; w^{-1/2} L w^{-1/2} w^{1/2} u = w^{1/2} u \; \Longrightarrow\; | |||
\tilde{L}\,\tilde{u} = \tilde{u} | |||
</math> | |||
with | |||
:<math> | |||
\tilde{L} \equiv w^{-1/2} L w^{-1/2} \quad\hbox{and}\quad \tilde{u} \equiv w^{1/2} u | |||
</math> | |||
Since ''w''(''x'') is positive-definite ''w''(''x'')<sup>−½</sup> is well-defined and real. The operator <math>\tilde{L}</math> is self-adjoint. | |||
--[[User:Paul Wormer|Paul Wormer]] 08:09, 14 October 2009 (UTC) |
Revision as of 02:09, 14 October 2009
Numbered equations
Hi Daniel,
I had to transform the templates provided in the WP article for numbered equations into plain old wikimarkup. I attempted to bring these templates over from WP, but they called many other templates and when I got them all over, the combined result didn't work. I decided to use a simple bit of html that defined a span with right justification and also defined an anchor. To reference the equation you then only need to insert a mediawiki markup referencing the anchor. It wouldn't be hard to turn this all into two templates if you think that would be useful. Dan Nessett 19:28, 2 September 2009 (UTC)
Redacted comment. I see it now.
Error
It seems to me that the article contains an error. Consider the equation:
Contrary to what is implied in the article, the operator L is not self-adjoint, unless 1/w(x) commutes with the operator to its right. This in general not the case. The proper way to transform is
with
Since w(x) is positive-definite w(x)−½ is well-defined and real. The operator is self-adjoint.
--Paul Wormer 08:09, 14 October 2009 (UTC)