Acceleration due to gravity: Difference between revisions

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Considering a body with the mass ''M'' as a source of a gravitational field, the strength of that field, or the
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gravitational acceleration, is given by <math>\vec g = -G \frac{M}{r^2} \frac{\vec{r}}{r}</math>.  
Where ''g'' is the '''acceleration due to gravity''', an object with mass ''m'' near the surface of Earth experiences a downward gravitational force of magnitude ''mg''. The quantity ''g'' has the dimension of acceleration, m s<sup>&minus;2</sup>, hence its name. Equivalently, it can be expressed in terms of force per unit mass, or N/kg in SI units.
The modulus of ''g'' is <math>g = G \frac{M}{r^2}</math>.


Here ''G'' is the gravitational constant, ''G'' = 6.67428&times;10<sup>-11</sup> Nm<sup>2</sup>/kg<sup>2</sup>, ''r'' is the distance between a body of mass ''m'' and the center of the gravitational field, <math>\vec r</math> is the vector radius of that body having the mass ''m''.
[[Gravitation#Newton's law of universal gravitation|Newton's gravitational law]] gives the following formula for ''g'',
If the source of the gravitational field has a spherical shape, then ''r'' is the sphere’s radius. Taking into
:<math>g = G\, \frac{M_{\mathrm{E}}}{R^2_{\mathrm{E}}},</math>
account that the Earth is an oblate spheroid, the distance ''r'' is not that of a sphere and varies from the
where ''G'' is the universal gravitational constant,<ref> Source: [http://physics.nist.gov/cgi-bin/cuu/Value?bg|search_for=Gravitational  CODATA 2006, retrieved 2/24/08 from NIST website]</ref> ''G'' = 6.67428 &times; 10<sup>&minus;11</sup>
equator to the poles.
m<sup>3</sup> kg<sup>&minus;1</sup> s<sup>&minus;2</sup>,
''M''<sub>E</sub> is the total mass of Earth, and ''R''<sub>E</sub> is the radius of Earth. This equation gives a good approximation, but is not exact. Deviations are caused by the [[centrifugal force]] due to the rotation of Earth around its axis, non-sphericity of Earth, and the non-homogeneity of the composition of Earth. These effects cause ''g'' to vary roughly &plusmn; 0.02 around the value 9.8 m s<sup>&minus;2</sup> from place to place on the surface of Earth. The quantity ''g'' is therefore referred to as the ''local gravitational acceleration''. It is measured as 9.78 m s<sup>&minus;2</sup> at the equator and 9.83 m s<sup>&minus;2</sup> at the poles.


[[Image:OblateSpheroidAngles.png]]
The 3rd [[General Conference on Weights and Measures]] (Conférence Générale des Poids et Mesures, CGPM) defined in 1901 a standard value denoted as ''g<sub>n</sub>''.<ref>[http://physics.nist.gov/Document/sp330.pdf The International System of Units (SI), NIST Special Publication 330, 2001 Edition] (pdf page 29 of 77 pdf pages)</ref>
<ref>[http://www.bipm.org/utils/common/pdf/si_brochure_8_en.pdf Bureau International des Poids et Mesures] (Brochure on SI, pdf page 51 of 88 pdf pages) From the website of the [[Bureau International des Poids et Mesures]]</ref> The value of the ''standard acceleration due to gravity'' ''g<sub>n</sub>'' is 9.80665 m s<sup>&minus;2</sup>. This value of ''g<sub>n</sub>'' was the conventional reference for calculating the now obsolete unit of force, the kilogram force, as the force needed for one kilogram of ''mass'' to accelerate at this value.


A normal section (on the equatorial plane) is almost an ellipse, so, ''r'' can be done by:
==References==
{{reflist}}


<math>r = \sqrt{{r_e}^2 cos^2 \theta + {r_p}^2 sin^2 \theta}</math>
[[Category:Suggestion Bot Tag]]
 
 
where ''r<sub>e</sub>'' and ''r<sub>p</sub>'' are the equatorial radius and polar radius, respectively and ''θ'' is the latitude, or
the angle made by ''r'' with the equatorial plane.
 
References
 
1. V.Dorobantu and Simona Pretorian, Physics between fear and respect, Vol. 3, Edited by Politehnica
                                          Timisoara, 2007, ISBN 978-973-625-493-2

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Where g is the acceleration due to gravity, an object with mass m near the surface of Earth experiences a downward gravitational force of magnitude mg. The quantity g has the dimension of acceleration, m s−2, hence its name. Equivalently, it can be expressed in terms of force per unit mass, or N/kg in SI units.

Newton's gravitational law gives the following formula for g,

where G is the universal gravitational constant,[1] G = 6.67428 × 10−11 m3 kg−1 s−2, ME is the total mass of Earth, and RE is the radius of Earth. This equation gives a good approximation, but is not exact. Deviations are caused by the centrifugal force due to the rotation of Earth around its axis, non-sphericity of Earth, and the non-homogeneity of the composition of Earth. These effects cause g to vary roughly ± 0.02 around the value 9.8 m s−2 from place to place on the surface of Earth. The quantity g is therefore referred to as the local gravitational acceleration. It is measured as 9.78 m s−2 at the equator and 9.83 m s−2 at the poles.

The 3rd General Conference on Weights and Measures (Conférence Générale des Poids et Mesures, CGPM) defined in 1901 a standard value denoted as gn.[2] [3] The value of the standard acceleration due to gravity gn is 9.80665 m s−2. This value of gn was the conventional reference for calculating the now obsolete unit of force, the kilogram force, as the force needed for one kilogram of mass to accelerate at this value.

References