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The set under consideration is analytic, and complete in the class of analytic sets; therefore it is not Borel. For more details see [[descriptive set theory]] and the book by [[Alexander_S._Kechris|Kechris]], especially Exercise (27.2) on page 209, Definition (22.9) on page 169, and Exercise (3.4)(ii) on page 14.
 
Usually, it is rather easy to prove that a given set is Borel (see below). It is much harder to prove that the set ''A'' is non-Borel; see [[Non-Borel_set/Advanced]] if you are acquainted with descriptive set theory. If you are not, you may find it instructive to try proving that ''A'' is Borel and observe a failure.
 
A. The set of all numbers ''x'' such that <math> a_0=3 </math> is an interval, therefore a Borel set.
 
B. The condition "<math> a_1=3 </math>" leads to a countable union of intervals; still a Borel set.
 
C. The same holds for the condition "<math> a_2=3 </math>" and, more generally, "<math> a_k=n </math>" for given ''k'' and ''n''.
 
D. The condition "<math> a_k<n </math>" leads to the union of finitely many sets treated in C; still a Borel set.
 
E. The condition "<math> a_k>n </math>" leads to the complement of a set treated in D; still a Borel set.
 
F. The condition "<math> a_k>n </math> for all ''k''" leads to the intersection of countably many sets treated in E; still a Borel set. The same holds for the condition "<math> a_k>7 </math> for all <math> k>3 </math>" and, more generally, "<math> a_k>n </math> for all <math> k>m </math>" for given <math> m,n. </math>
 
G. The condition "<math> a_k>7 </math> for all ''k'' large enough" leads to the union of countably many sets treated in F; still a Borel set.
 
H. The condition "the sequence <math> a_1, a_2, a_3, \dots </math> tends to infinity" leads to the intersection of countably many sets of the form treated in G ("7" being replaced with arbitrary natural number). Still a Borel set!
 
This list can be extended in many ways, but never reaches the set ''A''. Indeed, the definition of ''A'' involves arbitrary subsequences. For given <math> k_0 < k_1 < k_2 < \dots </math> the corresponding set is Borel. However, ''A'' is the union of such sets over all <math> k_0 < k_1 < k_2 < \dots </math>; a uncountable union!
 
Do not think, however, that uncountable union of Borel sets is always non-Borel. The matter is much more complicated since sometimes the same set may be represented also as a countable union (or countable intersection) of Borel sets. For instance, an interval is a uncountable union of single-point sets, which does not mean that the interval is non-Borel.

Latest revision as of 20:47, 30 June 2009

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An advanced level version of Non-Borel set.


Usually, it is rather easy to prove that a given set is Borel (see below). It is much harder to prove that the set A is non-Borel; see Non-Borel_set/Advanced if you are acquainted with descriptive set theory. If you are not, you may find it instructive to try proving that A is Borel and observe a failure.

A. The set of all numbers x such that is an interval, therefore a Borel set.

B. The condition "" leads to a countable union of intervals; still a Borel set.

C. The same holds for the condition "" and, more generally, "" for given k and n.

D. The condition "" leads to the union of finitely many sets treated in C; still a Borel set.

E. The condition "" leads to the complement of a set treated in D; still a Borel set.

F. The condition " for all k" leads to the intersection of countably many sets treated in E; still a Borel set. The same holds for the condition " for all " and, more generally, " for all " for given

G. The condition " for all k large enough" leads to the union of countably many sets treated in F; still a Borel set.

H. The condition "the sequence tends to infinity" leads to the intersection of countably many sets of the form treated in G ("7" being replaced with arbitrary natural number). Still a Borel set!

This list can be extended in many ways, but never reaches the set A. Indeed, the definition of A involves arbitrary subsequences. For given the corresponding set is Borel. However, A is the union of such sets over all ; a uncountable union!

Do not think, however, that uncountable union of Borel sets is always non-Borel. The matter is much more complicated since sometimes the same set may be represented also as a countable union (or countable intersection) of Borel sets. For instance, an interval is a uncountable union of single-point sets, which does not mean that the interval is non-Borel.