User:David MacQuigg/Sandbox/test math: Difference between revisions

Revision as of 03:22, 29 December 2021

Fissile: $_{92}^{235}U$ → 211.3 MeV → 86.75 TJ/kg. Crustal abundance 19.44 ppb. 4.83 MJ/liter.

Fertile: $_{92}^{238}U$ → $_{93}^{239}Pu$ → 211.5 MeV → 85.38 TJ/kg. Crustal abundance 2.7 ppm. 652 MJ/liter.

Fertile: $_{90}^{232}Th$ → $_{92}^{233}U$ → 200.1 MeV → 82.86 TJ/kg. Crustal abundance 12ppm. 2,813 MJ/liter.

Fusion: $_{3}^{6}Li$ + $_{1}^{2}H$ → $2\,_{2}^{4}He$ + 22.4 MeV → 270.2 TJ/kg. Crustal abundance 1.5 ppm. 1,150 MJ/liter.

$\sum _{m=1}^{\infty }\sum _{n=1}^{\infty }{\frac {m^{2}\,n}{3^{m}\left(m\,3^{n}+n\,3^{m}\right)}}$

An equivalent equation for the affine transformation is

b'_{i}=b_{i}\oplus b_{(i+4)mod8}\oplus b_{(i+5)mod8}\oplus b_{(i+6)mod8}\oplus b_{(i+7)mod8}\oplus c_{i}

where b' b and c are 8 bit arrays and c is 01100011.

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+Fissile: <math>^{235}_{92}U</math> → 211.3 MeV → 86.75 TJ/kg. Crustal abundance 19.44 ppb. 4.83 MJ/liter.
+Fertile: <math>^{238}_{92}U</math> → <math>^{239}_{93}Pu</math> → 211.5 MeV → 85.38 TJ/kg. Crustal abundance 2.7 ppm. 652 MJ/liter.
+Fertile: <math>^{232}_{90}Th</math> → <math>^{233}_{92}U</math> → 200.1 MeV → 82.86 TJ/kg. Crustal abundance 12ppm. 2,813 MJ/liter.
+Fusion:  <math>^6_3Li</math> + <math>^2_1H</math> → <math>2\,^4_2He</math> + 22.4 MeV → 270.2 TJ/kg. Crustal abundance 1.5 ppm. 1,150 MJ/liter.
+<math>\sum_{m=1}^\infty\sum_{n=1}^\infty\frac{m^2\,n}
+ {3^m\left(m\,3^n+n\,3^m\right)}</math>
 An equivalent equation for the affine transformation is
 : <math>b'_i = b_i \oplus b_{(i+4)mod8} \oplus b_{(i+5)mod8} \oplus b_{(i+6)mod8} \oplus b_{(i+7)mod8} \oplus c_i</math>
 where b' b and c are 8 bit arrays and c is 01100011.