Acceleration due to gravity: Difference between revisions
Jump to navigation
Jump to search
imported>Roger Moore No edit summary |
imported>Roger Moore No edit summary |
||
| Line 1: | Line 1: | ||
Under Newtonian gravity, the gravitational field strength, or gravitational acceleration, due to a point mass ''M'' is given by <math>\vec g = -G \frac{M}{r^2} \frac{\vec{r}}{r}</math>. | Under Newtonian gravity, the gravitational field strength, or gravitational acceleration, due to a point mass ''M'' is given by <math>\vec g = -G \frac{M}{r^2} \frac{\vec{r}}{r}</math>. | ||
The magnitude of | The magnitude of <math>\vec{g}</math> is <math>g = G \frac{M}{r^2}</math>. | ||
Here ''G'' is the gravitational constant, ''G'' = 6.67428×10<sup>-11</sup> Nm<sup>2</sup>/kg<sup>2</sup>, <math>\vec r</math> is the position vector in the field, relative to the point mass ''M'', and has a magnitude ''r''. | Here ''G'' is the gravitational constant, ''G'' = 6.67428×10<sup>-11</sup> Nm<sup>2</sup>/kg<sup>2</sup>, <math>\vec r</math> is the position vector in the field, relative to the point mass ''M'', and has a magnitude ''r''. | ||
Revision as of 17:18, 24 February 2008
Under Newtonian gravity, the gravitational field strength, or gravitational acceleration, due to a point mass M is given by . The magnitude of is .
Here G is the gravitational constant, G = 6.67428×10-11 Nm2/kg2, is the position vector in the field, relative to the point mass M, and has a magnitude r.
