Resultant (statics): Difference between revisions

From Citizendium
Jump to navigation Jump to search
imported>Richard Pinch
(New entry, just a stub)
 
imported>Todd Coles
No edit summary
 
(One intermediate revision by one other user not shown)
Line 1: Line 1:
In [[statics]] the '''resultant''' of a system of forces acting at various points on a rigid body or system of particles is a single force, acting at a single point, if one exists, which is equivalent to the given system.
{{subpages}}
In [[statics]] the '''resultant''' of a system of [[force]]s acting at various points on a rigid body or system of particles is a single force, acting at a single point, if one exists, which is equivalent to the given system.


Suppose that forces ''F''<sub>''i''</sub> act at points ''r''<sub>''i''</sub>.  The resultant would be a single force ''G'' acting at a point ''s''.  The systems are equivalent if they have the same net force and the same net [[moment of a force|moment]] about any point.
Suppose that forces ''F''<sub>''i''</sub> act at points ''r''<sub>''i''</sub>.  The resultant would be a single force ''G'' acting at a point ''s''.  The systems are equivalent if they have the same net force and the same net [[moment of a force|moment]] about any point.
Line 6: Line 7:


:<math>G = \sum_i F_i \,</math>
:<math>G = \sum_i F_i \,</math>
:<math>r \times G = \sum_i r_i \times F_i .</math>
:<math>s \times G = \sum_i r_i \times F_i .</math>
 
If <math>\sum_i r_i \times F_i = 0</math>, there is no net moment and the conditions are satisfied by taking <math>G = \sum_i F_i \,</math> and ''s''=0.
 
If <math>\sum_i r_i \times F_i \neq 0</math>, the second condition is soluble only if <math>\sum_i F_i \,</math> is perpendicular to <math>\sum_i r_i \times F_i</math>.  Suppose that this necessary condition is satisfied.  It is then the case that an appropriate ''s'' can be found. 
 
We conclude that a necessary and sufficient condition for the system of forces to have a resultant is that
 
:<math>\left(\sum_i F_i \right) \cdot \left(\sum_i r_i \times F_i \right) = 0 .\,</math>
 
==References==
* {{cite book | author=D.A. Quadling | coauthors=A.R.D. Ramsay | title=An Introduction to Advanced Mechanics | year=1964 | publisher=G. Bell and Sons | pages=102-103 }}

Latest revision as of 22:38, 17 February 2009

This article is developing and not approved.
Main Article
Discussion
Related Articles  [?]
Bibliography  [?]
External Links  [?]
Citable Version  [?]
 
This editable Main Article is under development and subject to a disclaimer.

In statics the resultant of a system of forces acting at various points on a rigid body or system of particles is a single force, acting at a single point, if one exists, which is equivalent to the given system.

Suppose that forces Fi act at points ri. The resultant would be a single force G acting at a point s. The systems are equivalent if they have the same net force and the same net moment about any point.

These condition are equivalent to requiring that

If , there is no net moment and the conditions are satisfied by taking and s=0.

If , the second condition is soluble only if is perpendicular to . Suppose that this necessary condition is satisfied. It is then the case that an appropriate s can be found.

We conclude that a necessary and sufficient condition for the system of forces to have a resultant is that

References

  • D.A. Quadling; A.R.D. Ramsay (1964). An Introduction to Advanced Mechanics. G. Bell and Sons, 102-103.