Normalisation (probability)

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In mathematical probability equations, which are used in nearly all branches of science, a normalization constant (or function) is often used to ensure that the sum of all probabilities totals one, or

 \sum{P_\mathrm{i}}  = 1

Probability distributions can be divided into two main groups: discrete probability distributions and continuous probability distributions.

Discrete Probability Distributions

Discrete probability distributions are used throughout gaming theory. Consider the simple example of rolling a pair of six-sided dice. Summing up the total roll of the dice yields the following possibilities:

Total (i)Possible outcomes (Die1,Die2)Occurrences (ni)
2 (1,1) 1
3 (1,2), (2,1) 2
4 (1,3), (3,1), (2,2) 3
5 (1,4), (4,1), (2,3), (3,2) 4
6 (1,5), (5,1), (2,4), (4,2), (3,3) 5
7 (1,6), (6,1), (2,5), (5,2), (3,4), (4,3) 6
8 (2,6), (6,2), (5,3), (3,5), (4,4) 5
9 (3,6), (6,3), (4,5), (5,4) 4
10 (4,6), (6,4), (5,5) 3
11 (5,6), (6,5) 2
12 (6,6) 1

Since the probability of any particular outcome is proportional to the number of ways it can occur

 \sum{P_\mathrm{i}}   = \sum{c_\mathrm{i}n_\mathrm{i}} = \sum{Nn_\mathrm{i}} = 1

where  c_\mathrm{i} is a coefficient of probability for outcome i. Assuming the dice are symmetrical we assume all values of  c_\mathrm{i} are equal and their sum equals 1.

Solving for N yields 1/36, the number of possible outcomes, so that the probability of total = i occurring are

 P_\mathrm{i} = \left(\frac{1}{36}\right)n_\mathrm{i} , and the sum of all probabilities is one

 \sum{P_\mathrm{i}} = \left(\frac{1}{36}\right)\left( 1 + 2 + 3+ 4 + 5 + 6 + 5 + 4 + 3 + 2 +1\right) = \frac{36}{36} = 1

Continuous probability distributions

In most scientific equations, probability functions are continuous functions, and the probability coefficients are sometimes functions rather than constants. For example, the zeta distribution with parameter s assigns probability proportional to 1/ns to the integer n: the normalizing factor is then the value of the Riemann zeta function

\zeta(s) = \sum_{n=1}^\infty \frac{1}{n^s} .
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